(X^2-6x+5)/(2x-2)=0

Solution for (X^2-6x+5)/(2x-2)=0 equation:

(X^2-6X+5)/(2X-2)=0


Domain of the equation: (2X-2)!=0

We move all terms containing X to the left, all other terms to the right

2X!=2

X!=2/2

X!=1

X∈R


We multiply all the terms by the denominator


(X^2-6X+5)=0

We get rid of parentheses

X^2-6X+5=0

a = 1; b = -6; c = +5;
Δ = b2-4ac
Δ = -62-4·1·5
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4}{2*1}=\frac{2}{2}
=1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4}{2*1}=\frac{10}{2}
=5
$